How much power does the gardener have to supply to push the lawnmower at a constant speed of 1.2 ?
Posted on January 18th, 2009 in gardener |
Alex H asked:
A gardener pushes a 12 lawn mower whose handle is tilted up 37 above horizontal. The lawn mower’s coefficient of rolling friction is 0.15. Assume his push is parallel to the handle.
A gardener pushes a 12 lawn mower whose handle is tilted up 37 above horizontal. The lawn mower’s coefficient of rolling friction is 0.15. Assume his push is parallel to the handle.
2 Responses
Hmmm,..that described activity may deprive “Mr. Gardener” of energy equal to calories in his meal of 3 tacos, or one beef & beans burrito or, 2 chicken fajitas or, 2 enchiladas.
dread’s got it right. you HAVE to consider the enchilada factor, typically 2.78224. without that, the equation is meaningless and a fraud.
I’d say .26 horsepower, if the rolling surface has no coefficient of drag and is horizontal. but what if the mower was an 11 instead of a 12, then what!!!